2(5x-1)+16=3(2x-2)+20-3x

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Solution for 2(5x-1)+16=3(2x-2)+20-3x equation: 



2(5x-1)+16=3(2x-2)+20-3x

We move all terms to the left:

2(5x-1)+16-(3(2x-2)+20-3x)=0

We multiply parentheses

10x-(3(2x-2)+20-3x)-2+16=0



We calculate terms in parentheses: -(3(2x-2)+20-3x), so:

3(2x-2)+20-3x

determiningTheFunctionDomain
3(2x-2)-3x+20

We add all the numbers together, and all the variables

-3x+3(2x-2)+20

We multiply parentheses

-3x+6x-6+20

We add all the numbers together, and all the variables

3x+14

Back to the equation:

-(3x+14)



We add all the numbers together, and all the variables

10x-(3x+14)+14=0

We get rid of parentheses

10x-3x-14+14=0

We add all the numbers together, and all the variables

7x=0

x=0/7

x=0

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