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2x(3x-2)-1=2x(3x-2)-1
We move all terms to the left:
2x(3x-2)-1-(2x(3x-2)-1)=0
We multiply parentheses
6x^2-4x-(2x(3x-2)-1)-1=0
We calculate terms in parentheses: -(2x(3x-2)-1), so:We get rid of parentheses
2x(3x-2)-1
We multiply parentheses
6x^2-4x-1
Back to the equation:
-(6x^2-4x-1)
6x^2-6x^2-4x+4x+1-1=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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