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2x(3x+7)-1=7x-5
We move all terms to the left:
2x(3x+7)-1-(7x-5)=0
We multiply parentheses
6x^2+14x-(7x-5)-1=0
We get rid of parentheses
6x^2+14x-7x+5-1=0
We add all the numbers together, and all the variables
6x^2+7x+4=0
a = 6; b = 7; c = +4;
Δ = b2-4ac
Δ = 72-4·6·4
Δ = -47
Delta is less than zero, so there is no solution for the equation
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