7x(3-1)+5=8x+3

Solution for 7x(3-1)+5=8x+3 equation:

7x(3-1)+5=8x+3

We move all terms to the left:

7x(3-1)+5-(8x+3)=0

We add all the numbers together, and all the variables

7x2-(8x+3)+5=0

We add all the numbers together, and all the variables

7x^2-(8x+3)+5=0

We get rid of parentheses

7x^2-8x-3+5=0

We add all the numbers together, and all the variables

7x^2-8x+2=0

a = 7; b = -8; c = +2;
Δ = b2-4ac
Δ = -82-4·7·2
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-2\sqrt{2}}{2*7}=\frac{8-2\sqrt{2}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+2\sqrt{2}}{2*7}=\frac{8+2\sqrt{2}}{14}
$