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4x(3-1)+5=7x+3
We move all terms to the left:
4x(3-1)+5-(7x+3)=0
We add all the numbers together, and all the variables
4x2-(7x+3)+5=0
We add all the numbers together, and all the variables
4x^2-(7x+3)+5=0
We get rid of parentheses
4x^2-7x-3+5=0
We add all the numbers together, and all the variables
4x^2-7x+2=0
a = 4; b = -7; c = +2;
Δ = b2-4ac
Δ = -72-4·4·2
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{17}}{2*4}=\frac{7-\sqrt{17}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{17}}{2*4}=\frac{7+\sqrt{17}}{8} $
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