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2x(3x+1)=6x-2
We move all terms to the left:
2x(3x+1)-(6x-2)=0
We multiply parentheses
6x^2+2x-(6x-2)=0
We get rid of parentheses
6x^2+2x-6x+2=0
We add all the numbers together, and all the variables
6x^2-4x+2=0
a = 6; b = -4; c = +2;
Δ = b2-4ac
Δ = -42-4·6·2
Δ = -32
Delta is less than zero, so there is no solution for the equation
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