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7(xx-2)+3(x+2)=5(x-6)
We move all terms to the left:
7(xx-2)+3(x+2)-(5(x-6))=0
We multiply parentheses
7x+3x-(5(x-6))-14+6=0
We calculate terms in parentheses: -(5(x-6)), so:We add all the numbers together, and all the variables
5(x-6)
We multiply parentheses
5x-30
Back to the equation:
-(5x-30)
10x-(5x-30)-8=0
We get rid of parentheses
10x-5x+30-8=0
We add all the numbers together, and all the variables
5x+22=0
We move all terms containing x to the left, all other terms to the right
5x=-22
x=-22/5
x=-4+2/5
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