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-1/4x-2=-3/2x+3
We move all terms to the left:
-1/4x-2-(-3/2x+3)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x+3)!=0We get rid of parentheses
x∈R
-1/4x+3/2x-3-2=0
We calculate fractions
(-2x)/8x^2+12x/8x^2-3-2=0
We add all the numbers together, and all the variables
(-2x)/8x^2+12x/8x^2-5=0
We multiply all the terms by the denominator
(-2x)+12x-5*8x^2=0
We add all the numbers together, and all the variables
12x+(-2x)-5*8x^2=0
Wy multiply elements
-40x^2+12x+(-2x)=0
We get rid of parentheses
-40x^2+12x-2x=0
We add all the numbers together, and all the variables
-40x^2+10x=0
a = -40; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-40)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-40}=\frac{-20}{-80} =1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-40}=\frac{0}{-80} =0 $
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