4(2xx-3)+8(x-4)=2(2x+6)

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Solution for 4(2xx-3)+8(x-4)=2(2x+6) equation: 



4(2xx-3)+8(x-4)=2(2x+6)

We move all terms to the left:

4(2xx-3)+8(x-4)-(2(2x+6))=0

We multiply parentheses

8x+8x-(2(2x+6))-12-32=0



We calculate terms in parentheses: -(2(2x+6)), so:

2(2x+6)

We multiply parentheses

4x+12

Back to the equation:

-(4x+12)



We add all the numbers together, and all the variables

16x-(4x+12)-44=0

We get rid of parentheses

16x-4x-12-44=0

We add all the numbers together, and all the variables

12x-56=0

We move all terms containing x to the left, all other terms to the right

12x=56

x=56/12

x=4+2/3

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