2v-4v+12=4(v-4)-2

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Solution for 2v-4v+12=4(v-4)-2 equation: 



2v-4v+12=4(v-4)-2

We move all terms to the left:

2v-4v+12-(4(v-4)-2)=0

We add all the numbers together, and all the variables

-2v-(4(v-4)-2)+12=0



We calculate terms in parentheses: -(4(v-4)-2), so:

4(v-4)-2

We multiply parentheses

4v-16-2

We add all the numbers together, and all the variables

4v-18

Back to the equation:

-(4v-18)



We get rid of parentheses

-2v-4v+18+12=0

We add all the numbers together, and all the variables

-6v+30=0

We move all terms containing v to the left, all other terms to the right

-6v=-30

v=-30/-6

v=+5

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