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(3/5)x=1/15
We move all terms to the left:
(3/5)x-(1/15)=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/5)x-(+1/15)=0
We multiply parentheses
3x^2-(+1/15)=0
We get rid of parentheses
3x^2-1/15=0
We multiply all the terms by the denominator
3x^2*15-1=0
Wy multiply elements
45x^2-1=0
a = 45; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·45·(-1)
Δ = 180
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{180}=\sqrt{36*5}=\sqrt{36}*\sqrt{5}=6\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{5}}{2*45}=\frac{0-6\sqrt{5}}{90} =-\frac{6\sqrt{5}}{90} =-\frac{\sqrt{5}}{15} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{5}}{2*45}=\frac{0+6\sqrt{5}}{90} =\frac{6\sqrt{5}}{90} =\frac{\sqrt{5}}{15} $
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