2/(z+1)=4/3z

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Solution for 2/(z+1)=4/3z equation: 



2/(z+1)=4/3z

We move all terms to the left:

2/(z+1)-(4/3z)=0



Domain of the equation: (z+1)!=0

We move all terms containing z to the left, all other terms to the right

z!=-1

z∈R





Domain of the equation: 3z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

2/(z+1)-(+4/3z)=0

We get rid of parentheses

2/(z+1)-4/3z=0

We calculate fractions


6z/(3z^2+3z)+(-4z-4)/(3z^2+3z)=0

We multiply all the terms by the denominator


6z+(-4z-4)=0

We get rid of parentheses

6z-4z-4=0

We add all the numbers together, and all the variables

2z-4=0

We move all terms containing z to the left, all other terms to the right

2z=4

z=4/2

z=2

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