2(2m)+4(4m+2)=2(2m)+4(4m+2)=108108

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Solution for 2(2m)+4(4m+2)=2(2m)+4(4m+2)=108108 equation: 



2(2m)+4(4m+2)=2(2m)+4(4m+2)=108108

We move all terms to the left:

2(2m)+4(4m+2)-(2(2m)+4(4m+2))=0

We multiply parentheses

22m+16m-(22m+4(4m+2))+8=0



We calculate terms in parentheses: -(22m+4(4m+2)), so:

22m+4(4m+2)

We multiply parentheses

22m+16m+8

We add all the numbers together, and all the variables

38m+8

Back to the equation:

-(38m+8)



We add all the numbers together, and all the variables

38m-(38m+8)+8=0

We get rid of parentheses

38m-38m-8+8=0

We add all the numbers together, and all the variables

=0

m=0/1

m=0

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