2m+3(m-12)=4m-20

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Solution for 2m+3(m-12)=4m-20 equation: 



2m+3(m-12)=4m-20

We move all terms to the left:

2m+3(m-12)-(4m-20)=0

We multiply parentheses

2m+3m-(4m-20)-36=0

We get rid of parentheses

2m+3m-4m+20-36=0

We add all the numbers together, and all the variables

m-16=0

We move all terms containing m to the left, all other terms to the right

m=16

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