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1/4x-1/3x=-1/2
We move all terms to the left:
1/4x-1/3x-(-1/2)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
1/4x-1/3x+1/2=0
We calculate fractions
36x^2/48x^2+12x/48x^2+(-16x)/48x^2=0
We multiply all the terms by the denominator
36x^2+12x+(-16x)=0
We get rid of parentheses
36x^2+12x-16x=0
We add all the numbers together, and all the variables
36x^2-4x=0
a = 36; b = -4; c = 0;
Δ = b2-4ac
Δ = -42-4·36·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4}{2*36}=\frac{0}{72} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4}{2*36}=\frac{8}{72} =1/9 $
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