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-2(v+5)=6v-2+4(2v+1)
We move all terms to the left:
-2(v+5)-(6v-2+4(2v+1))=0
We multiply parentheses
-2v-(6v-2+4(2v+1))-10=0
We calculate terms in parentheses: -(6v-2+4(2v+1)), so:We get rid of parentheses
6v-2+4(2v+1)
determiningTheFunctionDomain 6v+4(2v+1)-2
We multiply parentheses
6v+8v+4-2
We add all the numbers together, and all the variables
14v+2
Back to the equation:
-(14v+2)
-2v-14v-2-10=0
We add all the numbers together, and all the variables
-16v-12=0
We move all terms containing v to the left, all other terms to the right
-16v=12
v=12/-16
v=-3/4
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