4(y-4)-6=-5(-3y+2)-y

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Solution for 4(y-4)-6=-5(-3y+2)-y equation: 



4(y-4)-6=-5(-3y+2)-y

We move all terms to the left:

4(y-4)-6-(-5(-3y+2)-y)=0

We multiply parentheses

4y-(-5(-3y+2)-y)-16-6=0



We calculate terms in parentheses: -(-5(-3y+2)-y), so:

-5(-3y+2)-y

We add all the numbers together, and all the variables

-1y-5(-3y+2)

We multiply parentheses

-1y+15y-10

We add all the numbers together, and all the variables

14y-10

Back to the equation:

-(14y-10)



We add all the numbers together, and all the variables

4y-(14y-10)-22=0

We get rid of parentheses

4y-14y+10-22=0

We add all the numbers together, and all the variables

-10y-12=0

We move all terms containing y to the left, all other terms to the right

-10y=12

y=12/-10

y=-1+1/5

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