28=2(1u+3)

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Solution for 28=2(1u+3) equation: 



28=2(1u+3)

We move all terms to the left:

28-(2(1u+3))=0

We add all the numbers together, and all the variables

-(2(u+3))+28=0



We calculate terms in parentheses: -(2(u+3)), so:

2(u+3)

We multiply parentheses

2u+6

Back to the equation:

-(2u+6)



We get rid of parentheses

-2u-6+28=0

We add all the numbers together, and all the variables

-2u+22=0

We move all terms containing u to the left, all other terms to the right

-2u=-22

u=-22/-2

u=+11

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