34x2=68

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Solution for 34x2=68 equation:



34x^2=68
We move all terms to the left:
34x^2-(68)=0
a = 34; b = 0; c = -68;
Δ = b2-4ac
Δ = 02-4·34·(-68)
Δ = 9248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{9248}=\sqrt{4624*2}=\sqrt{4624}*\sqrt{2}=68\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-68\sqrt{2}}{2*34}=\frac{0-68\sqrt{2}}{68} =-\frac{68\sqrt{2}}{68} =-\sqrt{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+68\sqrt{2}}{2*34}=\frac{0+68\sqrt{2}}{68} =\frac{68\sqrt{2}}{68} =\sqrt{2} $

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