6(x-4)+9x=1/2(x+4)+3

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Solution for 6(x-4)+9x=1/2(x+4)+3 equation:



6(x-4)+9x=1/2(x+4)+3
We move all terms to the left:
6(x-4)+9x-(1/2(x+4)+3)=0
Domain of the equation: 2(x+4)+3)!=0
x∈R
We add all the numbers together, and all the variables
9x+6(x-4)-(1/2(x+4)+3)=0
We multiply parentheses
9x+6x-(1/2(x+4)+3)-24=0
We multiply all the terms by the denominator
9x*2(x+4)+3)+6x*2(x+4)+3)-(1-24*2(x+4)+3)=0
We add all the numbers together, and all the variables
9x*2(x+4)+3)+6x*2(x+4)+3)-(1-24*2(x=0
Wy multiply elements
18x^2(x+3)+6x*2(x+4)-24*2(x+3)-(1=0
We add all the numbers together, and all the variables
18x^2(x+3)+6x*2(x+4)-24*2(x+3)=0
Wy multiply elements
18x^2(x+3)+12x^2(x-48x(x=0

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