3(x-5)=7-2(x+1)

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Solution for 3(x-5)=7-2(x+1) equation: 



3(x-5)=7-2(x+1)

We move all terms to the left:

3(x-5)-(7-2(x+1))=0

We multiply parentheses

3x-(7-2(x+1))-15=0



We calculate terms in parentheses: -(7-2(x+1)), so:

7-2(x+1)

determiningTheFunctionDomain
-2(x+1)+7

We multiply parentheses

-2x-2+7

We add all the numbers together, and all the variables

-2x+5

Back to the equation:

-(-2x+5)



We get rid of parentheses

3x+2x-5-15=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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