253=(34-h)h

Solution for 253=(34-h)h equation:

253=(34-h)h

We move all terms to the left:

253-((34-h)h)=0

We add all the numbers together, and all the variables

-((-1h+34)h)+253=0


We calculate terms in parentheses: -((-1h+34)h), so:

(-1h+34)h

We multiply parentheses

-1h^2+34h

Back to the equation:

-(-1h^2+34h)


We get rid of parentheses

1h^2-34h+253=0

We add all the numbers together, and all the variables

h^2-34h+253=0

a = 1; b = -34; c = +253;
Δ = b2-4ac
Δ = -342-4·1·253
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-12}{2*1}=\frac{22}{2}
=11
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+12}{2*1}=\frac{46}{2}
=23
$