-3(2u-3)+3u=5+3(3u-4)

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Solution for -3(2u-3)+3u=5+3(3u-4) equation: 



-3(2u-3)+3u=5+3(3u-4)

We move all terms to the left:

-3(2u-3)+3u-(5+3(3u-4))=0

We add all the numbers together, and all the variables

3u-3(2u-3)-(5+3(3u-4))=0

We multiply parentheses

3u-6u-(5+3(3u-4))+9=0



We calculate terms in parentheses: -(5+3(3u-4)), so:

5+3(3u-4)

determiningTheFunctionDomain
3(3u-4)+5

We multiply parentheses

9u-12+5

We add all the numbers together, and all the variables

9u-7

Back to the equation:

-(9u-7)



We add all the numbers together, and all the variables

-3u-(9u-7)+9=0

We get rid of parentheses

-3u-9u+7+9=0

We add all the numbers together, and all the variables

-12u+16=0

We move all terms containing u to the left, all other terms to the right

-12u=-16

u=-16/-12

u=1+1/3

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