-2(-2y+3)-8y=2(y-7)-2

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Solution for -2(-2y+3)-8y=2(y-7)-2 equation: 



-2(-2y+3)-8y=2(y-7)-2

We move all terms to the left:

-2(-2y+3)-8y-(2(y-7)-2)=0

We add all the numbers together, and all the variables

-8y-2(-2y+3)-(2(y-7)-2)=0

We multiply parentheses

-8y+4y-(2(y-7)-2)-6=0



We calculate terms in parentheses: -(2(y-7)-2), so:

2(y-7)-2

We multiply parentheses

2y-14-2

We add all the numbers together, and all the variables

2y-16

Back to the equation:

-(2y-16)



We add all the numbers together, and all the variables

-4y-(2y-16)-6=0

We get rid of parentheses

-4y-2y+16-6=0

We add all the numbers together, and all the variables

-6y+10=0

We move all terms containing y to the left, all other terms to the right

-6y=-10

y=-10/-6

y=1+2/3

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