12(x+2)=3(x+2)+18

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Solution for 12(x+2)=3(x+2)+18 equation: 



12(x+2)=3(x+2)+18

We move all terms to the left:

12(x+2)-(3(x+2)+18)=0

We multiply parentheses

12x-(3(x+2)+18)+24=0



We calculate terms in parentheses: -(3(x+2)+18), so:

3(x+2)+18

We multiply parentheses

3x+6+18

We add all the numbers together, and all the variables

3x+24

Back to the equation:

-(3x+24)



We get rid of parentheses

12x-3x-24+24=0

We add all the numbers together, and all the variables

9x=0

x=0/9

x=0

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