2(x-3)=4x+4-2(-4x-3)

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Solution for 2(x-3)=4x+4-2(-4x-3) equation: 



2(x-3)=4x+4-2(-4x-3)

We move all terms to the left:

2(x-3)-(4x+4-2(-4x-3))=0

We multiply parentheses

2x-(4x+4-2(-4x-3))-6=0



We calculate terms in parentheses: -(4x+4-2(-4x-3)), so:

4x+4-2(-4x-3)

determiningTheFunctionDomain
4x-2(-4x-3)+4

We multiply parentheses

4x+8x+6+4

We add all the numbers together, and all the variables

12x+10

Back to the equation:

-(12x+10)



We get rid of parentheses

2x-12x-10-6=0

We add all the numbers together, and all the variables

-10x-16=0

We move all terms containing x to the left, all other terms to the right

-10x=16

x=16/-10

x=-1+3/5

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