22=6(x+1)+4

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Solution for 22=6(x+1)+4 equation: 



22=6(x+1)+4

We move all terms to the left:

22-(6(x+1)+4)=0



We calculate terms in parentheses: -(6(x+1)+4), so:

6(x+1)+4

We multiply parentheses

6x+6+4

We add all the numbers together, and all the variables

6x+10

Back to the equation:

-(6x+10)



We get rid of parentheses

-6x-10+22=0

We add all the numbers together, and all the variables

-6x+12=0

We move all terms containing x to the left, all other terms to the right

-6x=-12

x=-12/-6

x=+2

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