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225=x(x+16)
We move all terms to the left:
225-(x(x+16))=0
We calculate terms in parentheses: -(x(x+16)), so:We get rid of parentheses
x(x+16)
We multiply parentheses
x^2+16x
Back to the equation:
-(x^2+16x)
-x^2-16x+225=0
We add all the numbers together, and all the variables
-1x^2-16x+225=0
a = -1; b = -16; c = +225;
Δ = b2-4ac
Δ = -162-4·(-1)·225
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-34}{2*-1}=\frac{-18}{-2} =+9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+34}{2*-1}=\frac{50}{-2} =-25 $
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