7k-35=5(1+2k)=2k

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Solution for 7k-35=5(1+2k)=2k equation: 



7k-35=5(1+2k)=2k

We move all terms to the left:

7k-35-(5(1+2k))=0

We add all the numbers together, and all the variables

7k-(5(2k+1))-35=0



We calculate terms in parentheses: -(5(2k+1)), so:

5(2k+1)

We multiply parentheses

10k+5

Back to the equation:

-(10k+5)



We get rid of parentheses

7k-10k-5-35=0

We add all the numbers together, and all the variables

-3k-40=0

We move all terms containing k to the left, all other terms to the right

-3k=40

k=40/-3

k=-13+1/3

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