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8/x+1=x-1
We move all terms to the left:
8/x+1-(x-1)=0
Domain of the equation: x!=0We get rid of parentheses
x∈R
8/x-x+1+1=0
We multiply all the terms by the denominator
-x*x+1*x+1*x+8=0
We add all the numbers together, and all the variables
2x-x*x+8=0
Wy multiply elements
-1x^2+2x+8=0
a = -1; b = 2; c = +8;
Δ = b2-4ac
Δ = 22-4·(-1)·8
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6}{2*-1}=\frac{-8}{-2} =+4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6}{2*-1}=\frac{4}{-2} =-2 $
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