20(x-3)=10(x+1)-20

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Solution for 20(x-3)=10(x+1)-20 equation: 



20(x-3)=10(x+1)-20

We move all terms to the left:

20(x-3)-(10(x+1)-20)=0

We multiply parentheses

20x-(10(x+1)-20)-60=0



We calculate terms in parentheses: -(10(x+1)-20), so:

10(x+1)-20

We multiply parentheses

10x+10-20

We add all the numbers together, and all the variables

10x-10

Back to the equation:

-(10x-10)



We get rid of parentheses

20x-10x+10-60=0

We add all the numbers together, and all the variables

10x-50=0

We move all terms containing x to the left, all other terms to the right

10x=50

x=50/10

x=5

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