-6(t-7)+2(8t+3)=9(t+2)+2

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Solution for -6(t-7)+2(8t+3)=9(t+2)+2 equation: 



-6(t-7)+2(8t+3)=9(t+2)+2

We move all terms to the left:

-6(t-7)+2(8t+3)-(9(t+2)+2)=0

We multiply parentheses

-6t+16t-(9(t+2)+2)+42+6=0



We calculate terms in parentheses: -(9(t+2)+2), so:

9(t+2)+2

We multiply parentheses

9t+18+2

We add all the numbers together, and all the variables

9t+20

Back to the equation:

-(9t+20)



We add all the numbers together, and all the variables

10t-(9t+20)+48=0

We get rid of parentheses

10t-9t-20+48=0

We add all the numbers together, and all the variables

t+28=0

We move all terms containing t to the left, all other terms to the right

t=-28

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