4x=2/5x-10

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Solution for 4x=2/5x-10 equation:



4x=2/5x-10
We move all terms to the left:
4x-(2/5x-10)=0
Domain of the equation: 5x-10)!=0
x∈R
We get rid of parentheses
4x-2/5x+10=0
We multiply all the terms by the denominator
4x*5x+10*5x-2=0
Wy multiply elements
20x^2+50x-2=0
a = 20; b = 50; c = -2;
Δ = b2-4ac
Δ = 502-4·20·(-2)
Δ = 2660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{2660}=\sqrt{4*665}=\sqrt{4}*\sqrt{665}=2\sqrt{665}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{665}}{2*20}=\frac{-50-2\sqrt{665}}{40} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{665}}{2*20}=\frac{-50+2\sqrt{665}}{40} $

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