4u-4=2(3-u)-4

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Solution for 4u-4=2(3-u)-4 equation: 



4u-4=2(3-u)-4

We move all terms to the left:

4u-4-(2(3-u)-4)=0

We add all the numbers together, and all the variables

4u-(2(-1u+3)-4)-4=0



We calculate terms in parentheses: -(2(-1u+3)-4), so:

2(-1u+3)-4

We multiply parentheses

-2u+6-4

We add all the numbers together, and all the variables

-2u+2

Back to the equation:

-(-2u+2)



We get rid of parentheses

4u+2u-2-4=0

We add all the numbers together, and all the variables

6u-6=0

We move all terms containing u to the left, all other terms to the right

6u=6

u=6/6

u=1

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