20(3x-23)=19(x+4)

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Solution for 20(3x-23)=19(x+4) equation:



20(3x-23)=19(x+4)
We move all terms to the left:
20(3x-23)-(19(x+4))=0
We multiply parentheses
60x-(19(x+4))-460=0
We calculate terms in parentheses: -(19(x+4)), so:
19(x+4)
We multiply parentheses
19x+76
Back to the equation:
-(19x+76)
We get rid of parentheses
60x-19x-76-460=0
We add all the numbers together, and all the variables
41x-536=0
We move all terms containing x to the left, all other terms to the right
41x=536
x=536/41
x=13+3/41

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