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20x+(-5)=3(3x+3)-x
We move all terms to the left:
20x+(-5)-(3(3x+3)-x)=0
We add all the numbers together, and all the variables
20x-(3(3x+3)-x)-5=0
We calculate terms in parentheses: -(3(3x+3)-x), so:We get rid of parentheses
3(3x+3)-x
We add all the numbers together, and all the variables
-1x+3(3x+3)
We multiply parentheses
-1x+9x+9
We add all the numbers together, and all the variables
8x+9
Back to the equation:
-(8x+9)
20x-8x-9-5=0
We add all the numbers together, and all the variables
12x-14=0
We move all terms containing x to the left, all other terms to the right
12x=14
x=14/12
x=1+1/6
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