20x-1=2(9x-6)+x

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Solution for 20x-1=2(9x-6)+x equation: 



20x-1=2(9x-6)+x

We move all terms to the left:

20x-1-(2(9x-6)+x)=0



We calculate terms in parentheses: -(2(9x-6)+x), so:

2(9x-6)+x

We add all the numbers together, and all the variables

x+2(9x-6)

We multiply parentheses

x+18x-12

We add all the numbers together, and all the variables

19x-12

Back to the equation:

-(19x-12)



We get rid of parentheses

20x-19x+12-1=0

We add all the numbers together, and all the variables

x+11=0

We move all terms containing x to the left, all other terms to the right

x=-11

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