7x+8(x+x1/4)=3(6x-9)-8

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Solution for 7x+8(x+x1/4)=3(6x-9)-8 equation: 



7x+8(x+x1/4)=3(6x-9)-8

We move all terms to the left:

7x+8(x+x1/4)-(3(6x-9)-8)=0

We add all the numbers together, and all the variables

7x+8(+x+x1/4)-(3(6x-9)-8)=0

We multiply parentheses

7x+8x+8x-(3(6x-9)-8)=0



We calculate terms in parentheses: -(3(6x-9)-8), so:

3(6x-9)-8

We multiply parentheses

18x-27-8

We add all the numbers together, and all the variables

18x-35

Back to the equation:

-(18x-35)



We add all the numbers together, and all the variables

23x-(18x-35)=0

We get rid of parentheses

23x-18x+35=0

We add all the numbers together, and all the variables

5x+35=0

We move all terms containing x to the left, all other terms to the right

5x=-35

x=-35/5

x=-7

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