2/7x(-8+3)=26

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Solution for 2/7x(-8+3)=26 equation: 



2/7x(-8+3)=26

We move all terms to the left:

2/7x(-8+3)-(26)=0



Domain of the equation: 7x(-8+3)!=0

x∈R



We add all the numbers together, and all the variables

2/7x(-5)-26=0

We multiply all the terms by the denominator


-26*7x(-5)+2=0

Wy multiply elements

-182x(-+2=0

We use the square of the difference formula

-182x(-2=0

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