6(4x-7-2x)+19x-12=11(x+3)-7

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Solution for 6(4x-7-2x)+19x-12=11(x+3)-7 equation: 



6(4x-7-2x)+19x-12=11(x+3)-7

We move all terms to the left:

6(4x-7-2x)+19x-12-(11(x+3)-7)=0

We add all the numbers together, and all the variables

6(2x-7)+19x-(11(x+3)-7)-12=0

We add all the numbers together, and all the variables

19x+6(2x-7)-(11(x+3)-7)-12=0

We multiply parentheses

19x+12x-(11(x+3)-7)-42-12=0



We calculate terms in parentheses: -(11(x+3)-7), so:

11(x+3)-7

We multiply parentheses

11x+33-7

We add all the numbers together, and all the variables

11x+26

Back to the equation:

-(11x+26)



We add all the numbers together, and all the variables

31x-(11x+26)-54=0

We get rid of parentheses

31x-11x-26-54=0

We add all the numbers together, and all the variables

20x-80=0

We move all terms containing x to the left, all other terms to the right

20x=80

x=80/20

x=4

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