-5(4y-2)=2(3+6y)

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Solution for -5(4y-2)=2(3+6y) equation: 



-5(4y-2)=2(3+6y)

We move all terms to the left:

-5(4y-2)-(2(3+6y))=0

We add all the numbers together, and all the variables

-5(4y-2)-(2(6y+3))=0

We multiply parentheses

-20y-(2(6y+3))+10=0



We calculate terms in parentheses: -(2(6y+3)), so:

2(6y+3)

We multiply parentheses

12y+6

Back to the equation:

-(12y+6)



We get rid of parentheses

-20y-12y-6+10=0

We add all the numbers together, and all the variables

-32y+4=0

We move all terms containing y to the left, all other terms to the right

-32y=-4

y=-4/-32

y=1/8

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