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2/5x=5x+3
We move all terms to the left:
2/5x-(5x+3)=0
Domain of the equation: 5x!=0We get rid of parentheses
x!=0/5
x!=0
x∈R
2/5x-5x-3=0
We multiply all the terms by the denominator
-5x*5x-3*5x+2=0
Wy multiply elements
-25x^2-15x+2=0
a = -25; b = -15; c = +2;
Δ = b2-4ac
Δ = -152-4·(-25)·2
Δ = 425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{425}=\sqrt{25*17}=\sqrt{25}*\sqrt{17}=5\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-5\sqrt{17}}{2*-25}=\frac{15-5\sqrt{17}}{-50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+5\sqrt{17}}{2*-25}=\frac{15+5\sqrt{17}}{-50} $
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