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5x+8=25/4x
We move all terms to the left:
5x+8-(25/4x)=0
Domain of the equation: 4x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
5x-(+25/4x)+8=0
We get rid of parentheses
5x-25/4x+8=0
We multiply all the terms by the denominator
5x*4x+8*4x-25=0
Wy multiply elements
20x^2+32x-25=0
a = 20; b = 32; c = -25;
Δ = b2-4ac
Δ = 322-4·20·(-25)
Δ = 3024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3024}=\sqrt{144*21}=\sqrt{144}*\sqrt{21}=12\sqrt{21}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-12\sqrt{21}}{2*20}=\frac{-32-12\sqrt{21}}{40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+12\sqrt{21}}{2*20}=\frac{-32+12\sqrt{21}}{40} $
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