-x(x+4)=(x-4)(x-4)

Solution for -x(x+4)=(x-4)(x-4) equation:

-x(x+4)=(x-4)(x-4)

We move all terms to the left:

-x(x+4)-((x-4)(x-4))=0

We multiply parentheses

-x^2-4x-((x-4)(x-4))=0

We multiply parentheses ..

-x^2-((+x^2-4x-4x+16))-4x=0


We calculate terms in parentheses: -((+x^2-4x-4x+16)), so:

(+x^2-4x-4x+16)

We get rid of parentheses

x^2-4x-4x+16

We add all the numbers together, and all the variables

x^2-8x+16

Back to the equation:

-(x^2-8x+16)


We add all the numbers together, and all the variables

-1x^2-4x-(x^2-8x+16)=0

We get rid of parentheses

-1x^2-x^2-4x+8x-16=0

We add all the numbers together, and all the variables

-2x^2+4x-16=0

a = -2; b = 4; c = -16;
Δ = b2-4ac
Δ = 42-4·(-2)·(-16)
Δ = -112
Delta is less than zero, so there is no solution for the equation