2/3(6-3x)=(1-x)+(3-x

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Solution for 2/3(6-3x)=(1-x)+(3-x equation: 



2/3(6-3x)=(1-x)+(3-x

We move all terms to the left:

2/3(6-3x)-((1-x)+(3-x)=0



Domain of the equation: 3(6-3x)!=0

x∈R



We add all the numbers together, and all the variables

2/3(-3x+6)-((-1x+1)+(-1x+3)=0

We multiply all the terms by the denominator


-(((-1x+1)+(-1x+3))*3(-3x+6)+2=0

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