2(x-5)=2-3(5-2x)=16

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Solution for 2(x-5)=2-3(5-2x)=16 equation: 



2(x-5)=2-3(5-2x)=16

We move all terms to the left:

2(x-5)-(2-3(5-2x))=0

We add all the numbers together, and all the variables

2(x-5)-(2-3(-2x+5))=0

We multiply parentheses

2x-(2-3(-2x+5))-10=0



We calculate terms in parentheses: -(2-3(-2x+5)), so:

2-3(-2x+5)

determiningTheFunctionDomain
-3(-2x+5)+2

We multiply parentheses

6x-15+2

We add all the numbers together, and all the variables

6x-13

Back to the equation:

-(6x-13)



We get rid of parentheses

2x-6x+13-10=0

We add all the numbers together, and all the variables

-4x+3=0

We move all terms containing x to the left, all other terms to the right

-4x=-3

x=-3/-4

x=3/4

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