(3(6-z))/2=-z

Solution for (3(6-z))/2=-z equation:

(3(6-z))/2=-z

We move all terms to the left:

(3(6-z))/2-(-z)=0

We add all the numbers together, and all the variables

(3(-1z+6))/2-(-1z)=0

We get rid of parentheses

(3(-1z+6))/2+1z=0

We multiply all the terms by the denominator


(3(-1z+6))+1z*2=0


We calculate terms in parentheses: +(3(-1z+6)), so:

3(-1z+6)

We multiply parentheses

-3z+18

Back to the equation:

+(-3z+18)


Wy multiply elements

(-3z+18)+2z=0

We get rid of parentheses

-3z+2z+18=0

We add all the numbers together, and all the variables

-1z+18=0

We move all terms containing z to the left, all other terms to the right

-z=-18

z=-18/-1

z=+18