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4(x-2)+7=6x-2(1+x)
We move all terms to the left:
4(x-2)+7-(6x-2(1+x))=0
We add all the numbers together, and all the variables
4(x-2)-(6x-2(x+1))+7=0
We multiply parentheses
4x-(6x-2(x+1))-8+7=0
We calculate terms in parentheses: -(6x-2(x+1)), so:We add all the numbers together, and all the variables
6x-2(x+1)
We multiply parentheses
6x-2x-2
We add all the numbers together, and all the variables
4x-2
Back to the equation:
-(4x-2)
4x-(4x-2)-1=0
We get rid of parentheses
4x-4x+2-1=0
We add all the numbers together, and all the variables
1!=0
There is no solution for this equation
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