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1/3(x-4)=1/2(x-5)
We move all terms to the left:
1/3(x-4)-(1/2(x-5))=0
Domain of the equation: 3(x-4)!=0
x∈R
Domain of the equation: 2(x-5))!=0We calculate fractions
x∈R
(2xx/(3(x-4)*2(x-5)))+(-3xx/(3(x-4)*2(x-5)))=0
We calculate terms in parentheses: +(2xx/(3(x-4)*2(x-5))), so:
2xx/(3(x-4)*2(x-5))
We multiply all the terms by the denominator
2xx
Back to the equation:
+(2xx)
We calculate terms in parentheses: +(-3xx/(3(x-4)*2(x-5))), so:We get rid of parentheses
-3xx/(3(x-4)*2(x-5))
We multiply all the terms by the denominator
-3xx
Back to the equation:
+(-3xx)
2xx-3xx=0
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