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2(x+3)-2x=-(x-4)+2
We move all terms to the left:
2(x+3)-2x-(-(x-4)+2)=0
We add all the numbers together, and all the variables
-2x+2(x+3)-(-(x-4)+2)=0
We multiply parentheses
-2x+2x-(-(x-4)+2)+6=0
We calculate terms in parentheses: -(-(x-4)+2), so:We add all the numbers together, and all the variables
-(x-4)+2
We get rid of parentheses
-x+4+2
We add all the numbers together, and all the variables
-1x+6
Back to the equation:
-(-1x+6)
-(-1x+6)+6=0
We get rid of parentheses
1x-6+6=0
We add all the numbers together, and all the variables
x=0
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